Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • If the magnetic field component of the electromagnetic wave is <img alt="\vec{B}=\left(2.0 \times 10^{-7} \mathrm{wb} / \mathrm{m}^{2}\right) \sin \left[2 \pi\left(\frac{x}{18 \mathrm{~m}

If the magnetic field component of the electromagnetic wave is \vec{B}=\left(2.0 \times 10^{-7} \mathrm{wb} / \mathrm{m}^{2}\right) \sin \left[2 \pi\left(\frac{x}{18 \mathrm{~m}}-\frac{t}{6.0 \times 10^{-8} \mathrm{~s}}\right)\right] \hat{\mathrm{j}} then the intensity of the electromagnetic wave is (approximately)

Option: 1

5


Option: 2

4


Option: 3

3


Option: 4

6


Answers (1)

best_answer

 

 The average Intensity of electromagnetic waves is

I=\frac{1}{2}\frac{B_{o}^{2}}{\mu_{0}}c=\frac{1}{2}\times \frac{\left ( 2\times 10^{-7} \right )^{2}}{(4\pi \times 10^{-7})}\times 3\times 10^{8} =5

 

Posted by

shivangi.shekhar

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

BTech 2025 Admission LIVE: JoSAA round 1 reporting deadline extended, JAC Delhi, COMEDK counselling updates
anam-khan

Andhra launches free JEE, NEET coaching to over 1 lakh govt school students
anam-khan

JoSAA Counselling 2025 LIVE: BTech registration starts at josaa.nic.in for IIT, NIT, IIIT admissions

Latest Question