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  • If the phase difference between two sound waves of wavelength  is <img alt="60\degree" src="https://lea

If the phase difference between two sound waves of wavelength \lambda is 60\degree, the corresponding path difference is

Option: 1

\frac{\lambda}{6}


Option: 2

\frac{\lambda}{2}


Option: 3

2\lambda


Option: 4

\frac{\lambda}{4}


Option: 5

\frac{6}{\lambda}


Answers (1)

best_answer

As we had learnt in 

Phase -

The quantity \phi = wt+\delta is called the phase . It determines the status of the particle in simple harmonic motion.

 

 

- wherein

e.g. 

x= A\sin \left ( wt +\delta \right )\rightarrow phase

 

Path difference for a given phase difference \delta is given by

 

\Delta x= \frac{\lambda }{2\pi }\delta

Given \: that \: \delta = 60^{\circ}= \frac{\pi }{3}

\Delta x= \frac{\lambda }{2\pi }\times \frac{\pi }{3}

\therefore \:\Delta x= \: \frac{\lambda }{6}

 


 

Posted by

Pankaj Sanodiya

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