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If the resistance of a cell with cell constant $=3m^{-1}$ is $45\Omega$ then find the resistance if cell constant is changed to $9m^{-1}$ .
Option: 1
135

Option: 2
1.67

Option: 3
0.6

Option: 4
None

Answers (1)

best_answer

$R=\frac{\rho l}{A}= \frac{1}{k}\frac{l}{A}$

$45=\frac{1}{k}\times3$

$k=\frac{1}{15}$

If $\frac{l}{A}$ is changed to 9, then

$R=\frac{\rho l}{A}= \frac{1}{k}\frac{l}{A}=15\times9= 135$

Hence, the option number (1) is correct.

Posted by

vinayak

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