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  •   If the solubility of   gas in water at STP is 0.0729 m , calculate Henry's law constant </

 

If the solubility of Cl_2  gas in water at STP is 0.0729 m , calculate Henry's law constant 

Option: 1

815.5 


Option: 2

822.5 


Option: 3

840.5


Option: 4

838.5 


Answers (1)

best_answer

As we have learned

Henry's Law -

The mass of a gas dissolved in a given mass of solvent at any temperature is proportional to the pressure of the gas above the solvent.

- wherein

This amount decrease with increase in temperature.

 

 Solubility of Cl_2  = 0. 0729 m --. 0.0729 mole in 1 Kg solvent 

n _{ solvent } = \frac{1000}{18} = 55.55 \: moles

\therefore x_{Cl_2}= \frac{0.0729}{55.55+0.0729} = 0.0012

At STP  , P = 0.987 bar 

P_{Cl_2} = K_H X _{CL_2} \Rightarrow K_H= \frac{0.987 }{0.0012} = 822.5 \: \: bar

 

 

 

 

 

 

Posted by

vinayak

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