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In a plane electromagnetic wave the electric field oscillates sinusoidally at a frequency 2\times 10^{10}Hz and amplitude 48\frac{v}{m}. The amplitude of oscillating magnetic field will be

Option: 1

\frac{1}{16}\times 10^{-8}\frac{wb}{m^{2}}


Option: 2

16\times 10^{-8}\frac{wb}{m^{2}}


Option: 3

12\times 10^{-7}\frac{wb}{m^{2}}


Option: 4

\frac{1}{12}\times 10^{-7}\frac{wb}{m^{2}}


Answers (1)

best_answer

As we learned,

Relation between Eo and Bo -

E_{o}=c.B_{o}

- wherein

E_{o}= Electric field amplitude

B_{o} = Magnetic field amplitude

C= Speed of light in vacuum

 

So the magnitude of Oscillating mag. field

B=\frac{E}{C}= \frac{48}{3\times 10^{8}}= 16\times 10^{-8}

 

Posted by

Ritika Kankaria

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