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In an ac circuit, the current is  \mathrm{I=5 \sin \left(100 t-\frac{\pi}{2}\right) A} and the potential differences is V = 200 sin (100t) V. Then the power consumed is:

Option: 1

200 W


Option: 2

500 W


Option: 3

1000 W


Option: 4

Zero


Answers (1)

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Here, \mathrm{\left[=5 \sin \left(100 t-\frac{\pi}{2}\right) A\right. }
\mathrm{\mathrm{V}=200 \sin (100 \mathrm{t}) \mathrm{V} }
\mathrm{\therefore \quad } Phase difference between \mathrm{\mathrm{V}\, \, and\, \, \mathrm{I}\, \, is\, \, \phi=\frac{\pi}{2} }
Power consumed, \mathrm{\mathrm{P}=\mathrm{V}_{\mathrm{rms}} \mathrm{I}_{\mathrm{rms}} }
\mathrm{\cos \phi\, \, \mathrm{V}_{\mathrm{ms}} \mathrm{I}_{\mathrm{rms}} \cos 90^{\circ}=zero }

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Irshad Anwar

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