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In certain region gravitation force  F= \frac{mK}{r^{2}}[ m is mass and k is constant]. Find the value of gravitational potential.

Option: 1

 

\frac{-k}{r}

 


Option: 2

\frac{2k}{r}


Option: 3

\frac{k}{r}


Option: 4

\frac{-2k}{r}


Answers (1)

best_answer

 As we learn

Relation between Potential and Potential energy -

U=\frac{-GMm}{r}=m\left [ \frac{-GM}{r} \right ]

U\rightarrow Potential energy

r\rightarrow distance

- wherein

U=mV

V\rightarrow Potential

m\rightarrow mass

U\rightarrow Potential energy

 

 F=\frac{mk}{r^{2}}

U=-\int Fdr

U=-\int \frac{mk}{r^{2}}dr

U=-mk\int \frac{1}{r^{2}}dr =-mk\left [ -\frac{1}{r} \right ]=\frac{mk}{r}

Gravitational Potential

V=\frac{u}{m}=\left ( \frac{\frac{mk}{r}}{m} \right )=\frac{k}{r}

 

Posted by

Riya

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