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In periodic table the $Po$ belongs to
Option: 1
4th period

Option: 2
5th period

Option: 3
6th period

Option: 4
7th period

Answers (1)

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As we learnt

Electronic configuration of Po (84) -

$\left [ Xe \right ]4f^{14}5d^{10}6S^{2}6P^{4}$

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Posted by

HARSH KANKARIA

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