Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • In the coordination compound , <img alt="\mathrm{K_{4}\left [ Ni(CN)_{4} \right ],}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7BK_%7B4%7D%5Cleft%20%5B%20Ni%28CN%29_%7B4%7D%20%

In the coordination compound , \mathrm{K_{4}\left [ Ni(CN)_{4} \right ],} the oxidation state of nickel is

Option: 1

-1


Option: 2

0


Option: 3

+1


Option: 4

+2


Answers (1)

In \mathrm{K_{4}\left [ Ni\left ( CN \right )_{4} \right ]},

Let the oxidation number of Ni be x.

\therefore  +4+x-4=0

\Rightarrow x=0

Hence, the oxidation state of Nickel in the given complex is Zero(0). 

Therefore, option (2) is correct.

Posted by

Sumit Saini

View full answer

Similar Questions

Latest Question