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Q
In the given circuit diagram, the currents, I1 = -0.3 A, I4 = 0.8 A and I5 = 0.4 A, areflowing as shown. The currents I2 , I3 and I6 ,respectively, are :
Answers (1)
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Kirchoff's first law -
- wherein
Apply Kcl at Q
I6+I3 = I1+ I2 .........(1)
I1 = 0.3A
I4 = 0.8A
I5 = 0.4A
KCL at 5
I4= I5 +I3
I3 = I4 - I5
= 0.8 +0.4
=0.4A
KCL at R
I1+I2 = I4
I2 = I4 - I1
= 0.8 - (-0.3)
=1.1A
From equation (1)
I6 + I3 = I1+ I2
I6 = I1 + I2 - I3
= -0.3+1.1 -0.4
=0.4A
I2 = 1.1A
I3 = 0.4A
I6 = 0.4A
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