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In the given circuit, it is observed that the current $I$ is independent of the value of the resistance $R_6$ . Then the resistance values must satisfy

Option: 1
$R_1 R_2 R_5=R_3 R_4 R_6$

Option: 2
$\frac{1}{R_5}+\frac{1}{R_6}=\frac{1}{R_1+R_2}+\frac{1}{R_3+R_4}$

Option: 3
$R_1 R_4=R_2 R_3$

Option: 4
$R_1 R_3=R_2 R_4=R_5 R_6$

Answers (1)

best_answer

Since current $I$ is independent of $R_6$ , it follows that the resistances $R_1, R_2, R_3$ and $R_4$ must form a balanced Wheatstone bridge.
$\therefore \quad (c)$

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