Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • In the given diagram if force of 160 N is applied then what is the acceleration (in m/s2)  of block? <img alt="" src="https://cdn.entrance360.com/media/uploads/2

In the given diagram if force of 160 N is applied then what is the acceleration (in m/s2)  of block?

Option: 1

4


Option: 2

0


Option: 3

6


Option: 4

8


Answers (1)

As we learned

Acceleration of Block on horizontal surface -

ma = P - FK

a=\frac{P-F_{K}}{m}

a = acceleration

FK= kinetic friction

- wherein

This is the case of acceleration against friction.

 

 fL=\mu _{s}N\Rightarrow 0.6*200=120 N 

N= mg =20 X 10 =200 N

f> f_{L}  hence,body will move

Kinetic friction fk will act on body in opposite direction.

\sum f= ma

160-80 =20\times a

    a=\frac{80}{20}=4m/s^{2}

 

Posted by

Kshitij

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

Andhra launches free JEE, NEET coaching to over 1 lakh govt school students
anam-khan

JoSAA Counselling 2025 LIVE: BTech registration starts at josaa.nic.in for IIT, NIT, IIIT admissions
anam-khan

Kota: 17-year old student from UP preparing for JEE dies of electrocution in hostel

Latest Question