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In which of the following cases the reaction will proceed towards reactant side ? 

Option: 1

Q_c > K_c


Option: 2

Q_c < K_c


Option: 3

\Delta G >0


Option: 4

Both a and c 


Answers (1)

best_answer

As we have learned

Thermodynamics of the reaction -

\bigtriangleup G>0

- wherein

The reaction is considered non-spontaneous. Instead, as reverse reaction would have a negative \bigtriangleup G, the product of forward reaction shall be converted to the reactant. 

 

 If   Q_c >K_c and \bigtriangleup G>0 , in such cases the reaction proceeds towards reactant side 

If Q_c <K_c  , then reaction proceeds towards product side 

 

Posted by

Ritika Kankaria

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