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  • In which of the following ionization processes the bond energy has increased and also the magnetic behaviour has changed from paramagnetic to diamagnetic Op

In which of the following ionization processes the bond energy has increased and also the magnetic behaviour has changed from paramagnetic to diamagnetic 

Option: 1

NO\rightarrow NO^{+}


Option: 2

N_{2}\rightarrow N_{2}^{+}


Option: 3

C_{2}\rightarrow C_{2}^{+}


Option: 4

O_{2}\rightarrow O_{2}^{+}


Answers (1)

best_answer

Magnetic behavior of molecule -

If  all the molecular orbital's electrons in a molecule are doubly occupied, the substance is diamagnetic

Bond strength -

The energy required to break one mole of bonds of a particular type in the gaseous state is called bond energy or bond strength.

we know,

Bond energy \propto  Bond order

Now,

Electronic config of  NO=\left[(\sigma_{1s})^{2}(\sigma^{*}_{1s})^{2}(\sigma_{2s})^{2}(\sigma^{*}_{2s})^{2}(\pi_{2py})^{2}(\pi_{2pz})^{2}(\sigma_{2px})^{2}(\pi^{*}_{2py})^{1} \right ]   

\therefore B.O = \frac{1}{2}\left ( 10-5 \right )=2.5

 Electronic config of NO^{+}=\left[(\sigma_{1s})^{2}(\sigma^{*}_{1s})^{2}(\sigma_{2s})^{2}(\sigma^{*}_{2s})^{2}(\pi_{2py})^{2}(\pi_{2pz})^{2}(\sigma_{2px})^{2}(\pi^{*}_{2py})^{0}(\pi^{*}_{2px})^{0} \right ]

\therefore B.O = \frac{1}{2}\left ( 10-4 \right )=3

Since there are no unpaired electrons in NO+ as there are in NO, 

NO+ is diamagnetic while NO is paramagnetic due to 1 unpaired electron.

Posted by

Ritika Jonwal

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