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  • In Young’s double slit experiment, instead of taking slits of equal widths, one slit is made twice as wide as the other. Then in the interference pattern:O

In Young’s double slit experiment, instead of taking slits of equal widths, one slit is made twice as wide as the other. Then in the interference pattern:

Option: 1

The intensities of both the maxima and the minima increase


Option: 2

The intensity of maxima increases and the minima has zero intensity


Option: 3

The intensity of maxima decreases and that of the minima increases


Option: 4

The intensity of maxima decreases and the minima has zero intensity


Answers (1)

best_answer

As we have learned 

Maximum amplitude & Intensity -

When \theta = 0,2\pi ---2n\pi
 

- wherein

A_{max }= A_{1}+A_{2}

I_{max }= \left ( \sqrt{I_{1}}+\sqrt{I_{2}} \right )^{2}

 

 

Minimum amplitude & Intensity -

\theta = \left ( 2n+1 \right )\pi
 

- wherein

A_{min }= A_{1}-A_{2}

I_{min }= \left ( \sqrt{I_{1}}-\sqrt{I_{2}} \right )^{2}

 

  

If one slit is made rwice that of other than  

I_2 = 4I_1

I^{max }= (\sqrt I_1+\sqrt I_2)^2 = 9 I_1 \\I^{min }= I_1

Hence intensity of both maxima and minima increases 

Posted by

vinayak

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