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In Young's double slit experiment, the two slits acts as coherent sources of equal amplitude A and wavelength \mathrm{\lambda}. In another experiment with the same set up the two slits are sources of equal amplitude A and wavelength \mathrm{\lambda} but are incoherent. The ratio of the intensity of light at the mid-point of the screen in the first case to that in the second case is:

Option: 1

4 : 1


Option: 2

1 : 1


Option: 3

2 : 1


Option: 4

1 : 4


Answers (1)

best_answer

Intensity in the first case, \mathrm{\mathrm{I}_1=4 \mathrm{I}_0}

Where, \mathrm{\mathrm{I}_0=}  intensity due to each source

Intensity in second case, \mathrm{\mathrm{I}_2=2 \mathrm{I}_0}

\mathrm{ \therefore \quad \frac{\mathrm{I}_1}{\mathrm{I}_2}=\frac{4 \mathrm{I}_0}{2 \mathrm{I}_0}=\frac{2}{1} }

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Pankaj

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