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  • Let   where <img alt="l=2.0\pm 0.1,Z=1.0\pm 0.1" src="

Let y=l^{2}-\frac{l^{3}}{Z}  where l=2.0\pm 0.1,Z=1.0\pm 0.1 then the value of 'y'  is given by :

Option: 1

+2\pm 0.8


Option: 2

-4\pm 1.6


Option: 3

-4\pm 0.8


Option: 4

None of these


Answers (1)

best_answer

 y = l ^{2}-\frac{l^{3}}{Z}

dy=2l dl -\left ( \frac{Z3l ^{2}dl -l ^{3}dZ}{Z^{2}} \right )=\left ( 2l -\frac{3l ^{2}}{Z} \right )dl +\frac{ l ^{3}}{Z^{2}}dZdy=\left ( 2\times 2-\frac{3\times 2^{2}}{1} \right )\left ( \pm 0.1 \right )+\frac{8}{1}\left ( \pm 0.1 \right )

dy=\left | -8\left ( \pm 0.1 \right ) \right |+8\left ( \pm 0.1 \right )|=\pm 1.6

y=l ^{2}-\frac{l ^{3}}{Z^{2}}= 2^{2}-\frac{2^{3}}{1}=4-8=-4

\therefore y=-4\pm 1.6

Posted by

Sanket Gandhi

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