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  • Moment of inertia of semi-circular ring about an axis which is perpendicular to the plane of the ring and passes through the centre Option: 1 <i

Moment of inertia of semi-circular ring about an axis which is perpendicular to the plane of the ring and passes through the centre 

Option: 1

MR^{2}

 

 

 


Option: 2

2MR^{2}


Option: 3

\frac{MR^{2}}{2}


Option: 4

\frac{MR^{2}}{4}


Answers (1)

best_answer

 

 

Moment of inertia for Ring -

I= MR^{2}

- wherein

About an axis perpendicular to the ring & passing through centre .

 

 If we consider whole ring then

{I}'=(2M)R^{2}

For half ring I=\frac{{I}'}{2}=\frac{(2M)R^{2}}{2}

I=MR^{2}

Posted by

Ritika Harsh

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