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In figure is shown a system of four capacitors connected across a 10 V battery. Charge that will flow from switch S when it is closed is :

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@Sahala 

In figure is shown a system of four capacitors connected across a 10 V battery. Charge that will flow from switch S when it is closed is :

Answer:

 

For upper and lower links

 C_{eq}= \frac{6}{5}\mu F

\therefore Q_{upper}= Q_{lower}= 12\mu C

On closing switch charge on 2\mu F is 10\mu C and that on 3\mu F is 15\mu C.

At a and b 

q_{i}= -12+12= 0 (because switch S is opened so there will be no charge flow)

q_{f}= 15-10= 5\mu C

\therefore 5\mu C flows from b to a. 

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sudhir.kumar

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