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A monochromatic light is incident at a certain angle on an equilateral triangular prism and suffers minimum deviation. If the refractive index of the material of the prism is $\sqrt{3}$ , then the angle of incidence is:

Option 1)

$60^{\circ}$

Option 2)

$30^{\circ}$
Option 3)

$90^{\circ}$
Option 4)

$45^{\circ}$

Answers (1)

best_answer

Relation between angle of incidence and angle of refaction -

$\mu _{1}\sin i= \mu _{2}\sin r$

- wherein

$\mu _{1}=$ refractive index of medium of incidence.

$\mu _{2}=$ refractive index of medium where rays is refracted.

$i=$ angle of incidence.

$r=$ angle of refraction.

$\mu =\sqrt{3}$

For minimum deviation

$i=e$

& $r_{1}=r_{2}=\frac{A}{2}=30^{\circ}$

apply snell law

$1\times \sin i=\sqrt{3}\times \frac{1}{2}=\frac{\sqrt{3}}{2}$

$i=60^{\circ}$

Option 1)

$60^{\circ}$

Option 2)

$30^{\circ}$

Option 3)

$90^{\circ}$

Option 4)

$45^{\circ}$

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