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  • Need clarity, kindly explain! A player caught a cricket ball of mass 150 g moving at a rate of 20 m/s . If the catching process is completed in 0.1 s the force of the blow exerted by the ball on the hand of the player is equal to

A player caught a cricket ball of mass 150 g  moving  at a rate of 20 m/s . If the catching process is completed in 0.1 s  the force of the blow exerted by the ball on the hand of the player is equal to

  • Option 1)

    300 N

  • Option 2)

    150 N

  • Option 3)

    3 N

  • Option 4)

    30 N

 

Answers (2)

best_answer

As we learnt in

Impulse Momentum Theorem -

\vec{F}=\frac{d\vec{p}}{dt}

\int_{t_{1}}^{t_{2}}\vec{F}dt=\int_{p_{1}}^{p_{2}}\vec{dp}

- wherein

If \bigtriangleup t  is increased, average force is decreased

 

 

 

Force \times time = Impulse = Change of momentum

\therefore\: \: \: \: Force= \frac{Impulse}{time}= \frac{3}{0.1}= 30 N

Correct option is 4.


Option 1)

300 N

This is an incorrect option.

Option 2)

150 N

This is an incorrect option.

Option 3)

3 N

This is an incorrect option.

Option 4)

30 N

This is the correct option.

Posted by

SudhirSol

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30 N

Posted by

Aadesh

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