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Assume that a neutron breaks into a proton and an electron. The energy released during this process is (Mass of neutron = 1.6725 x 10–27kg; mass of proton = 1.6725 x 10–27kg; mass of electron = 9 x 10–31 kg)

 
  • Option 1)

    0.73 MeV

  • Option 2)

    7.10 MeV

  • Option 3)

    6.30 MeV

  • Option 4)

    0.51 MeV

 

Answers (1)

best_answer

Mass defect, \Delta m=m_{p}+m_{e}-m_{n}

=(1.6725\times 10^{-27}+9\times 10^{-31}-1.6725\times 10^{-27})kg

=9\times 10^{-31}kg

Energy \; released=\Delta mc^{2}

=9\times 10^{-31}\times (3\times 10^{8})^{2}J

=\frac{9\times 10^{-31}\times 9\times 10^{16}}{1.6\times 10^{-13}}MeV

=0.51MeV


Option 1)

0.73 MeV

Option 2)

7.10 MeV

Option 3)

6.30 MeV

Option 4)

0.51 MeV

Posted by

SudhirSol

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