Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa

A projectile is fired with initial velocity v at an angle \theta, has timeof descent T. If the initial velocity be reduced to half at the same angle of projection then Time of descent becomes

  • Option 1)

    \frac{T}{}4

  • Option 2)

    \frac{T}{}2

  • Option 3)

    2T

  • Option 4)

    4T

 

Answers (1)

best_answer

Time of descent is time taken in moving downward

so As we know time taken to reach highest point from the ground(time of ascent) = time taken to come back to ground from highest point(time of descent) = T

0 = vsin(\theta)-gT

T = \frac{vsin(\theta)}{g}

velovity is reduced to half and angle is same implies that new time of descent will be  T/2

Posted by

Vishwash Tetarwal

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2024 session 2 result date announced; Steps to check NTA session 2 scores
anam-khan

JEE Main 2024 session 2 final answer key soon at jeemain.nta.ac.in; result on April 25
anam-khan

JEE Main 2024 Session 2: Last day to challenge answer key today

Latest Question