Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa

Two stones re projected fom the same point with same speed making angles 45o + \theta and 45o - \theta with the horizontal respectively. If \theta \leq 45\degree, then the horizontal ranges of the two stones are in the ratio of

  • Option 1)

    1:1

  • Option 2)

    1:2

  • Option 3)

    1:3

  • Option 4)

    1:4

 

Answers (1)

best_answer

let Horizontal Range be R_{1} and R_{2}.

R_{1}=\frac{ u^{2}sin(2(45^{o}+\theta))}{g}=\frac{u^{2}sin(90^{o}+2\theta)}{g}=\frac{u^{2}cos(2\theta)}{g}

R_{2}=\frac{ u^{2}sin(2(45^{o}-\theta))}{g}=\frac{u^{2}sin(90^{o}-2\theta)}{g}=\frac{u^{2}cos(2\theta)}{g}

both are equal so ratio would be 1:1.

 

Posted by

Vishwash Tetarwal

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2026 application correction begins on jeemain.nta.nic.in; edit details by December 2
anam-khan

JEE Mains 2026 LIVE: NTA to conduct session 1 from January 21 to 30; exam pattern, syllabus
anam-khan

JEE Main 2026 correction window opens tomorrow; NTA allows exam city change

Latest Question