Two spheres of radius a and b respectively are charged and joined by a wire. The ratio of electric field of the spheres is
a/b
b/a
As we learned
Outside the sphere (P lies outside the sphere) -
- wherein
- surface charge density.
Joined by a wire means they are at the same potential. For same potential
Further, the electric field at the surface of the sphere having radius R and charge Q is
Option 1)
a/b
Option 2)
b/a
Option 3)
Option 4)
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