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  • Need explanation for: - Differential equations - JEE Main

Degree of differential equation \left ( \frac{d^{3}y}{dx^{3}} \right )^{5}-\left ( \frac{d^{2}y}{dx^{2}} \right )^{10}+1=0  is

  • Option 1)

    5

  • Option 2)

    10

  • Option 3)

    2

  • Option 4)

    3

 

Answers (1)

best_answer

As we learnt

 

Degree of a Differential Equation -

 

Degree of Highest order differential coefficient appearing in it, provided it can be expressed as a polynomial equation in derivatives

- wherein

\left ( \frac{dy}{dx} \right )^{2}+3\left ( \frac{dy}{dx} \right )-5=0

Degree = 2

 

 Degree of third order derivative term,when all derivatives are already in form of polynomial equation in derivative is 5. So degree is 5.

 


Option 1)

5

Option 2)

10

Option 3)

2

Option 4)

3

Posted by

Himanshu

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