Get Answers to all your Questions

header-bg qa

Hall-Heroult's process is given by :

  • Option 1)

    Cu^{2+}(aq)+H_{2}(g)\rightarrow Cu(s)+2H^{+}(aq)

  • Option 2)

    Cr_{2}O_{3}+2Al \rightarrow Al_{2}O_{3}+2Cr

  • Option 3)

    2Al_{2}O_{3}+3C\rightarrow 4Al +3CO_{2}

  • Option 4)

    ZnO+C\overset{Coke,1673K}{\rightarrow}Zn+CO

     

Answers (1)

best_answer

 

Thermodynamic principle of Metallurgy -

\bigtriangleup G=\bigtriangleup H-T\bigtriangleup S

also \bigtriangleup G^{\circ}= -RTlnK

- wherein

K is equilibrium constant.If \bigtriangleup G  for a reaction is negative reaction is fusible.

 

 

Minerals -

The various compounds of metals which occur in the earth's crust and are obtained by mining are called minerals

- wherein

In the earth crust order of abundance of elements is O>Si>Al>Fe

 

 

Reduction of Metal Oxide to Metal -

The crude metal is obtained when the roasted ore or calcined ore is put to reduction by using a suitable reducing agent.

- wherein

HgO+HgS\rightarrow 3Hg+SO2

As we have learnt in Hall - Heroult's process

The following reaction occurs:

2Al_{2}O_{3} + 3C\rightarrow 4Al+3CO_{2}

2Al_{2}O_{3} (l) \rightleftharpoons 4Al^{3+}(l)+6O^{-2}(l)

At cathode : 4Al^{3+} +12^{e-}\rightarrow 4Al(l)

At anode :  6O^{2-}(l)\rightarrow 3O_{2}(g)+12e^{-}

3C+3O_{2}\rightarrow 3CO_{2}

 


Option 1)

Cu^{2+}(aq)+H_{2}(g)\rightarrow Cu(s)+2H^{+}(aq)

Option 2)

Cr_{2}O_{3}+2Al \rightarrow Al_{2}O_{3}+2Cr

Option 3)

2Al_{2}O_{3}+3C\rightarrow 4Al +3CO_{2}

Option 4)

ZnO+C\overset{Coke,1673K}{\rightarrow}Zn+CO

 

Posted by

admin

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE