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  • Need explanation for: - If the de Broglie wavelength of the electron in nthBohr orbit in a hydrogenic atom is equal to 1.5 - Atomic Structure - JEE Main

If the de Broglie wavelength of the electron in n th Bohr orbit in a hydrogenic atom is equal to 1.5 \pi a_{0}(a0 is Bohr radius), then the value of n/z is :

 

  • Option 1)

    0.75

  • Option 2)

    1.0

  • Option 3)

    1.50

  • Option 4)

    0.40

Answers (1)

best_answer

 

De-broglie wavelength -

\lambda = \frac{h}{mv}= \frac{h}{p}

- wherein

where m is the mass of the particle

v its velocity 

p its momentum

 

 

 

Atomic number ( Z ) -

Z = number of protons in the nucleus of an atom

As we have learned in debroglics wavelength

we know

2\pi r\gamma =n\lambda

2\pi\: d_{0}\: \frac{n^{2}}{z}=n\lambda

2\pi\: a_{0}\: \frac{n^{2}}{z}=n_{1}\: 5\: \pi\: a_{0}

\frac{n}{z}=\frac{1.5}{2}=\frac{3}{4}

-

 

 


Option 1)

0.75

Option 2)

1.0

Option 3)

1.50

Option 4)

0.40

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