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  • Need explanation for: - Sets, Relations and Functions - JEE Main-3

Find the domain of the function  f(x)=\frac{1}{x+1},

 

  • Option 1)

    R-\left \{ 1 \right \}

     

     

     

  • Option 2)

    R-\left \{- 1 \right \}

  • Option 3)

    \left \{- 1 ,1\right \}

  • Option 4)

    R

 

Answers (1)

best_answer

As we learned

 

Rational Function -

f(x )= \frac{\rho \left ( x \right )}{q\left ( x \right )} Where \rho \left ( x \right )\: \: and\: \: q\left ( x \right ) polynomials in x.

 

 

- wherein

Domin of this function is R-\left \{ x:q\left ( x \right )= 0 \right \} Range depends on function.

 

 The function is not defined whenx+1=0\; or\; x=-1.

Hence the domain is R-(-1). The range is the set of all real numbers or R.

 


Option 1)

R-\left \{ 1 \right \}

 

 

 

Option 2)

R-\left \{- 1 \right \}

Option 3)

\left \{- 1 ,1\right \}

Option 4)

R

Posted by

gaurav

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