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A solution of Al_{2}(SO)_{4} \left \{ d = 1.253gm/ml \right \}  contain 22% salt by weight. The molarity, normality and molality of the solution is

  • Option 1)

    0.805 M, 4.83 N, 0.825 M

  • Option 2)

    0.825 M, 48.3 N, 0.805 M

  • Option 3)

    4.83 M, 4.83 N, 4.83 M

  • Option 4)

    None

 

Answers (1)

As we learned

 

Molality -

Molality = \frac{Moles \: of \: solute}{Mass \, \: o\! f\: solution(Kg)}

-

 

 Molarity = \frac{{0}/_{0} 10\times d }{GMM}=\frac{22\times 10\times 1.253}{342}=0.805M.

Normality = \frac{{0}/_{0} 10\times d }{GEM}=\frac{22\times 10\times 1.253}{342/6}=4.83N.

Molality = \frac{22\times 1000}{342(100-22)}=0.825m


Option 1)

0.805 M, 4.83 N, 0.825 M

Option 2)

0.825 M, 48.3 N, 0.805 M

Option 3)

4.83 M, 4.83 N, 4.83 M

Option 4)

None

Posted by

Vakul

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