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  • One mole of an ideal gas is taken from state A to state B by three different processes, (a) ACB (b) ADB (c) AEB as shown in the P - V diagram. The heat absorbed by the gas is :

One mole of an ideal gas is taken from state A to state B by three different processes, (a) ACB (b) ADB (c) AEB as shown in the P - V diagram. The heat absorbed by the gas is :

Option: 1

greater in process (B) then in (A)   


Option: 2

the least in process (B)                                                     

     


Option: 3

 the same in (A) and (C)                            

 


Option: 4

 less in (C) then in (B)


Answers (1)

best_answer

 

First law of Thermodynamics -

Heat imported to a body in is in general used to increase internal energy and work done against external pressure.

- wherein

dQ= dU+dW

 

 

Change in internal energy for cyclic process -

\Delta U= 0
 

- wherein

Since in a cyclic process initial and final state is same.

U_{f}= U_{i}

 

 

 Heat absorbed by gas in three processes is given by

Q_{ACB}= \Delta U + W_{ACB}

Q_{ADB}= \Delta U

Q_{AEB}= \Delta U +W_{AEB}

The change in internal energy in all the three cases is same. And W_{ACB} is +ve, W_{AEB} is –ve.

 Hence Q_{ABC}> Q_{ADB}> Q_{AEB}

Posted by

Irshad Anwar

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