partial pressure of n2 in mixture of 7g n2 & 8g Ar having total pressure 27kg/cm2
Given:7g of N2 i.e 0.25 moles
8g of Ar i.e 0.2 moles
Total pressure=27bars
Explanation:
we know that moles=Given mass /molecular mass
Now we know that
partial pressure is equal to product of moles fraction and total pressure in closed system
therefore,
mole fraction of Nitrogen gas=0.25/0.45
Now partial pressure=(0.25/0.45)27
=15bars
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