Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa

A negatively charged plate has charge density of 2\times 10^{-6}C/m^2. The initial distance of an electron which is moving toward plate, cannot strike the plate, if it is having energy of 200 eV

  • Option 1)

    1.77mm

  • Option 2)

    3.51mm

  • Option 3)

    1.77cm

  • Option 4)

    3.51 cm

 

Answers (1)

best_answer

As we have learnt,

 

Work energy relation -

W= U_{f}-U_{i}

 

 

- wherein

U_{f}- \, final\, P.E

U_{i}-\, initial\, P.E.

 

 Let an electron is projected towards the plate from the r distance as shown in fig. 

It will not strike the plate if and only if KE \leq e(E\cdot r)  (where E = Electric field due to charge plate = \frac{\sigma}{2\epsilon_0} )

 

\Rightarrow r \geq \frac{KE}{eE}. Hence maximum value of R is given by

r = \frac{KE}{eE} = \frac{200eV}{e\times\frac{\sigma}{2\epsilon_{0}}} = \frac{200\times8.86\times10^{-12}}{2\times 10^{-6}} = 1.77mm


Option 1)

1.77mm

Option 2)

3.51mm

Option 3)

1.77cm

Option 4)

3.51 cm

Posted by

Aadil

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2026: IIT Roorkee’s ECE emerges as top choice after CSE; closing rank rises
anam-khan

JEE Main 2026 application correction begins on jeemain.nta.nic.in; edit details by December 2
anam-khan

JEE Mains 2026 LIVE: NTA to conduct session 1 from January 21 to 30; exam pattern, syllabus

Latest Question