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In S_{N}2 reaction ,the correct order of reactivity for the following compounds:CH_{3}Cl,CH_{3}CH_{2}Cl,(CH_{3})_{2}CHCl\: and\: (CH_{3}) _{3}CCl is

  • Option 1)

    CH_{3}Cl> (CH_{3})_{2}CHCl> CH_{3}CH_{2}Cl> \left ( CH_{3} \right )_{3}CCl

  • Option 2)

    CH_{3}Cl> CH_{3}CH_{2}Cl> \left ( CH_{3} \right )_{2}CHCl> \left ( CH_{3} \right )_{3}CCl

  • Option 3)

    CH_{3} CH_{2}Cl> \left CH_{3} \right Cl> \left ( CH_{3} \right )_{2}CHCl> \left ( CH_{3} \right )_{3}CCl

  • Option 4)

    \left ( CH_{3} \right )_{2}CHCl> CH_{3}CH_{2}Cl> CH_{3}Cl> \left ( CH_{3} \right )_{3}CCl

 

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As we learned

Reactivity Order of alkyl halides -

1^{\circ}Alkyl\: Halide> 2^{\circ}Alkyl\: Halide> 3^{\circ}Alkyl \: Halide

 

- wherein

1^{\circ}Alkyl\: Halide> 2^{\circ}Alkyl\: Halide> 3^{\circ}Alkyl \: Halide

Inhibition by steric hindrance SN2 reactions are particularly sensitive to steric factors, since they are greatly retarded by steric hindrance (crowding) at the site of reaction. In general, the order of reactivity of alkyl halides in SN2 reactions is: methyl  > 1> 2o> 3o

 

 

 

 

 

SN2 reaction are sensitive to  steric factors, these are retarded by steric hindrance at the site of reaction.


Option 1)

CH_{3}Cl> (CH_{3})_{2}CHCl> CH_{3}CH_{2}Cl> \left ( CH_{3} \right )_{3}CCl

Option 2)

CH_{3}Cl> CH_{3}CH_{2}Cl> \left ( CH_{3} \right )_{2}CHCl> \left ( CH_{3} \right )_{3}CCl

Option 3)

CH_{3} CH_{2}Cl> \left CH_{3} \right Cl> \left ( CH_{3} \right )_{2}CHCl> \left ( CH_{3} \right )_{3}CCl

Option 4)

\left ( CH_{3} \right )_{2}CHCl> CH_{3}CH_{2}Cl> CH_{3}Cl> \left ( CH_{3} \right )_{3}CCl

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