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A simple pendulum of length 1 m is oscillating with an angular frequency 10 rad/s . The support of the pendulum starts oscillating up and down with a small angular frequency 1 rad/s and an amplitude of 10-2 m. The relative change in the angular frequency of the pendulum is best given by :

  • Option 1)

     1 rad/s

  • Option 2)

    10-3 rad/s

  • Option 3)

    10-5 rad/s

  • Option 4)

    10-1 rad/s

Answers (1)

best_answer

 

Time period of oscillation of simple pendulum -

T=2\pi \sqrt{\frac{l}{g}}

- wherein

l = length of pendulum 

g = acceleration due to gravity.

 

 


Option 1)

 1 rad/s

Option 2)

10-3 rad/s

Option 3)

10-5 rad/s

Option 4)

10-1 rad/s

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