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 From the top of a 64 metres high tower, a stone is thrown upwards vertically with the velocity of 48 m/s. The greatest height (in metres) attained by the stone, assuming the value of the gravitational acceleration g=32 m/s2, is :

  • Option 1)

    100

  • Option 2)

    88

  • Option 3)

    128

  • Option 4)

    112

 

Answers (1)

best_answer

As we have learned

Collinear Vectors -

Two vectors are said to be collinear if their directed line segments are parallel disregards to their direction. 

- wherein

If \vec{a} and \vec{b} are collinear , then \vec{a}= K\vec{b} where K \epsilon R

 

 

Negative of a vector -

The negative of a vector is collinear with vector itself.

- wherein

-\vec{a} is collinear with \vec{a}

 

 v^2 = a ^ 2 + 2al \\\Rightarrow 0 = (48)^2 - 2 \times 32 \times 5 \\ \Rightarrow S = \frac{48 \times 48}{64} = 36 m

So , height = 64 + 36 = 100 

 

 


Option 1)

100

Option 2)

88

Option 3)

128

Option 4)

112

Posted by

Himanshu

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