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  • Please,please help me - Redox Reaction and Electrochemistry - JEE Main-4

Resistance of a cell is 50 \Omega when the substance's resistivity is 25 \Omega m. In a similar cell if we use a substance of 35 \Omega m, what would be the new resistance of the cell be?

  • Option 1)

    70\Omega

  • Option 2)

    60 \Omega

  • Option 3)

    35 \Omega

  • Option 4)

    50 \Omega

 

Answers (1)

best_answer

As we have learnt,

 

Cell Constant -

R = \rho \frac{l}{A}

G^{*} =\frac{l}{A}=\frac{R}{\rho }=\kappa R

 

- wherein

The quantity \frac{l}{A} is called cell constant denoted by the symbol \varphi^{*}. It depends on the distance between the electrodes and their area of cross section.

 

 50 = 25\times \frac{l}{A} \Rightarrow \frac{l}{A} = 2m^{-1}

then, if \rho = 35

then new R = \frac{\rho l}{A} = 35\times 2 = 70 \Omega


Option 1)

70\Omega

Option 2)

60 \Omega

Option 3)

35 \Omega

Option 4)

50 \Omega

Posted by

Plabita

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