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  • Please,please help me - Redox Reaction and Electrochemistry - JEE Main-6

Match the column I with column II

a) Kohlrausch Law            p) \frac{\Lambda_m}{\Lambda_m^o}

b) {\Lambda_m}                               q) \frac{1}{R}\times \frac{l}{}A

c) K                                    r) \Lambda_{m\;Ca_3 (PO_4)_2}^o = 3\lambda^o_{Ca^{2+}} + 2\lambda^o_{PO_4^{3-}}

c) \alpha                                   s) K\times \frac{1000}{M}

  • Option 1)

    a -r , b- s, c- q , d -p

  • Option 2)

    a -s , b- r, c- q , d -p

  • Option 3)

    a -r , b- s, c- p , d -q

  • Option 4)

    a -s , b- r, c- p , d -q

 

Answers (1)

best_answer

As we  have learnt,

 

Application of Kohlrausch's law -

Determination of Degree of dissociation of weak electrolytes.

- wherein

Degree of dissociation

\alpha = \frac{\Lambda m}{\Lambda_{m}^{0} }

 

i is correct 

 


Option 1)

a -r , b- s, c- q , d -p

Option 2)

a -s , b- r, c- q , d -p

Option 3)

a -r , b- s, c- p , d -q

Option 4)

a -s , b- r, c- p , d -q

Posted by

Aadil

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