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  • Please,please help me Two equal resistance when connected in series to a battery, consume electric power of 60W. If these resistance are now connected in parallel combination to the same battery, the electric power consumed will be:

Two equal resistance when connected in series to a battery, consume electric power of 60W. If these resistance are now connected in parallel combination to the same battery, the electric power consumed will be:

 

  • Option 1)

    120W

  • Option 2)

    240 W

  • Option 3)

    30 W

  • Option 4)

    60 W

Answers (1)

best_answer

 

Power dissipiated in external resistance -

P=(\frac{E}{R+r})^{2}R

-

R_{1}=\frac{V^{2}}{P_{1}}=\frac{220^{2}}{25}

R_{2}=\frac{V^{2}}{P_{2}}=\frac{220^{2}}{100}

I=\frac{220}{R_{1}+R_{2}}=\frac{220}{\frac{220^{2}}{25}+\frac{220^{2}}{100}}

=\frac{20}{220}A

P_{1}=I^{2}R_{1}=(\frac{20}{220})^{2}.\frac{220^{2}}{25}

=16\: \omega

P_{2}=I^{2}R_{2}=(\frac{20}{220})^{2}\times \frac{220^{2}}{100}

=4\: \omega

 

 

 

 


Option 1)

120W

Option 2)

240 W

Option 3)

30 W

Option 4)

60 W

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