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Engineering
5 months, 1 week ago

Point charge Q in fixed on (d, 0, 0) another charge Q is placed at (0, 0, 0). What should be the value of q sothat Q at origin will be in e

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A Avinash Dongre
Answered 3 months, 1 week ago

  

given F on Q at 0 = zero

\therefore \frac{KQq}{\left ( \frac{d}{2} \right )^{2}} + \frac{kQ^{2}}{d^{2}} = 0

4 q = - Q

q = \frac{-Q}{4}

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