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  • Rate of a catalysed and an uncatalysed reaction can be equal if:Option: 1 Both reaction temperature are equal <div class

Rate of a catalysed and an uncatalysed reaction can be equal if:

Option: 1

Both reaction temperature are equal 


Option: 2

Temperature of the uncatalysed reaction is more than the catalysed reaction.


Option: 3

Temperature of the uncatalysed reaction is less than the catalysed reaction.


Option: 4

Rate of catalysed reaction cannot be equal to uncatalysed reaction in any case. 


Answers (1)

best_answer

Consider a rate of reaction with catalysed and uncatalysed condition.
\mathrm{ k=A e^{-E_a / R T} \ldots \ldots \text { eqn }(1) }
\mathrm{ k_{\text {cat }}=A e^{-E_a^{\prime} / R T} \ldots \ldots \text { eqn }(2)
\mathrm{ k } : Rate constant without catalyst
\mathrm{ k_{\text {cut }}} : Rate constant with catalyst
\mathrm{E_a:} Activation energy without catalyst
\mathrm{E_a^{\prime}} : Activation energy with catalyst
Assuming the rate of reaction of catalysed and the uncatalysed reactions are equal,
\mathrm{ A e^{-E_a / R T_1}=A e^{-E_a^{\prime} / R T_2} }
\mathrm{ T_1: }Temperature at which uncatalysed reaction occurs
\mathrm{ T_2: } : Temperature at which catalysed reaction occur

\mathrm{ e^{-E_{\mathrm{a}} / R T_1}=e^{-E_a^{\prime} / R T_2} }
Taking natural logarithm on both side

\mathrm{ \frac{-E_a}{RT_1}=\frac{-E_a^{\prime}}{RT_2} }

\mathrm{ \frac{E_a}{T_1}=\frac{E_a^{\prime}}{T_2} }
Since,

\mathrm{ E_a>E_a^{\prime} }
\mathrm{ T_1>T_2 }.

Posted by

shivangi.shekhar

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