Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Refracting angle of prism A=600 and its r.i. is  . The

Refracting angle of prism A=600 and its r.i. is \mu =\frac{3}{2} . The angle of incidence i to get minimum deviation is :

Option: 1

30o


Option: 2

45o


Option: 3

\sin ^{-1}(\frac{3}{4})

 


Option: 4

\sin ^{-1}(\frac{3}{5})


Answers (1)

best_answer

As we learn @2463

Condition of minimum deviation -

i=e

 

 

- wherein

\delta _{min}= 2i-A

\mu = \frac{\sin \left ( \frac{\delta _{m}+A}{2} \right )}{\sin \left ( A/2 \right )}

For minimum deviation

\mu = \frac{\sin \left ( \frac{\delta _{m}+A}{2} \right )}{\sin \left ( A/2 \right )}or\frac{3}{2}=\frac{\sin\frac{(60+\delta _{m})}{2}}{\sin 30}

or \sin \left ( \frac{60+\delta _{m}}{2} \right )=\frac{3}{4}

\Rightarrow i=\frac{A+\delta _{m}}{2}=\sin ^{-1}\left ( \frac{3}{4} \right )

 

 

 

Posted by

Ajit Kumar Dubey

View full answer

Similar Questions

Latest Question