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Resolving power of a microscope depends upon

Option: 1

Wavelength of light used, directly


Option: 2

Wavelength of light used, inversely


Option: 3

Frequency of light used


Option: 4

Focal length of objective


Answers (1)

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Resolving power of microscope -

Resolving power of microscope: 

\text { R.L. }=\frac{\lambda}{2 \mu \sin \theta} \text { and } R . P .=\frac{2 \mu \sin \theta}{\lambda} \Rightarrow R . P . \propto \frac{1}{\lambda}

λ =Wavelength of light used to illuminate the object,

μ = Refractive index of the medium between object and objective,

θ = Half angle of the cone of light from the point object

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Divya Prakash Singh

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