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  • Solve! Chargeq is uniformly distributed over a thin half ring of radius R. The electric field at the centre of the ring is

Charge q  is uniformly distributed over a thin half ring of radius R . The electric field at the centre of the ring is

 

  • Option 1)

    \frac{q}{2\pi ^{2}\varepsilon_{0}R^{2}}

     

     

     

  • Option 2)

    \frac{q}{4\pi ^{2}\varepsilon_{0}R^{2}}

  • Option 3)

    \frac{q}{4\pi\varepsilon_{0}R^{2}}

  • Option 4)

    \frac{q}{2\pi\varepsilon_{0}R^{2}}

 

Answers (1)

best_answer

As we learned

 

Charged Circular ring -

A charged circular ring of radius R and charge Q.

- wherein

 

 From figure dl  = R d\theta ,

Charge on dl  = \lambda Rd\theta \left \{ \lambda \frac{q}{\pi R} \right \}

Electric field at centre due to dl is  dE=k\cdot \frac{\lambda Rd\theta }{R^{2}}\cdot

 


Option 1)

\frac{q}{2\pi ^{2}\varepsilon_{0}R^{2}}

 

 

 

Option 2)

\frac{q}{4\pi ^{2}\varepsilon_{0}R^{2}}

Option 3)

\frac{q}{4\pi\varepsilon_{0}R^{2}}

Option 4)

\frac{q}{2\pi\varepsilon_{0}R^{2}}

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