The sum of all real values of x satisfying the equation
is
3
-4
6
5
As we have learned
Roots of Quadratic Equation with real Coefficients -
are roots if
is satisfied by
- wherein
Also there is a case
(x-3)(x-2)= 0
= x = 2,3
For x = 3 :
So sum 4+1+6+(-10)+2= 3
Option 1)
3
Option 2)
-4
Option 3)
6
Option 4)
5