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  • Solve it, A homogenous solid cylindrical roller of radius R and mass M is pulled on a cricket pitch by a horizontal force. Assuming rolling without slipping, angular acceleration of the cylinder is:

A homogenous solid cylindrical roller of radius R and mass M is pulled on a cricket pitch by a horizontal force. Assuming rolling without slipping, angular acceleration of the cylinder is:

  • Option 1)

     \frac{3F}{2 m R}

       

       

      

  • Option 2)

    \frac{F}{3 m R}

  • Option 3)

    \frac{F}{2 m R}

  • Option 4)

    \frac{2F}{3 m R}

Answers (1)

best_answer

 

Analogue of second law of motion for pure rotation -

\vec{\tau }=I\, \alpha

- wherein

Torque equation can be applied only about two point

(i) centre of motion.

(ii) point which has zero velocity/acceleration.

Condition of rolling without sliping. Point of contact of wheel and ground is at rest. 

T about\: P = I\alpha

FR = \frac{3}{2}MR^{2}\alpha

\alpha =\frac{2F}{3MR}

 


Option 1)

 \frac{3F}{2 m R}

   

   

  

Option 2)

\frac{F}{3 m R}

Option 3)

\frac{F}{2 m R}

Option 4)

\frac{2F}{3 m R}
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