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  • Solve it, An electric dipole is situated in an electric field of uniform intensity E whose dipole moment is p and moment of inertia is I. If the dipole is displaced slightly from the equilibrium position, then the angular frequency of its oscillation

An electric dipole is situated in an electric field of uniform intensity E whose dipole moment is p and moment of inertia is I. If the dipole is displaced slightly from the equilibrium position, then the angular frequency of its oscillations is

  • Option 1)

    \left ( \frac{pE}{I} \right )^{1/2}

  • Option 2)

    \left ( \frac{pE}{I} \right )^{3/2}

  • Option 3)

    \left ( \frac{I}{pE} \right )^{1/2}

  • Option 4)

    \left ( \frac{p}{IE} \right )^{1/2}

 

Answers (3)

best_answer

As we have learned

Oscillation of dipole -

T=2\pi \sqrt{\frac{I}{PE}}

- wherein

I - Moment of Inertia of dipole.

 

 

When dipole is given a small angular displacement q  about it's equilibrium position, the restoring torque will be

\tau = - pE \sin \theta= -pE\theta      (as sinq = q)

or I\frac{d^2\theta }{dt^2}= -pE\theta     (as \tau = I\alpha I\frac{d^2\theta }{dt^2} )

or \frac{d^2\theta }{dt^2}= \omega ^2\theta  with \frac{pE}{I}\Rightarrow \omega = \sqrt{\frac{pE}{I}} 

 


Option 1)

\left ( \frac{pE}{I} \right )^{1/2}

Option 2)

\left ( \frac{pE}{I} \right )^{3/2}

Option 3)

\left ( \frac{I}{pE} \right )^{1/2}

Option 4)

\left ( \frac{p}{IE} \right )^{1/2}

Posted by

Aadil

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Posted by

Bharat

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Option 1 is correct answer

Posted by

Sindhu

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