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  • Solve it, Formation of real image using a biconvex lens is shown below : If the whole set up is immersed in water without disturbing the object and the screen positions , what will one observe on the screen ?

 Formation of real image using a biconvex lens is shown below : 

If the whole set up is immersed in water without disturbing the object and the screen positions , what will one observe on the screen ?

 

 

 

  • Option 1)

    Erect real image

  • Option 2)

    Image disappears

  • Option 3)

    Magnified image

  • Option 4)

     No change

Answers (1)

best_answer

 

Lensmaker's Formula -

\frac{1}{f}= \left ( \frac{\mu _{2}}{\mu _{1}}-1 \right )\left ( \frac{1}{R_{1}}- \frac{1}{R_{2}}\right )
 

- wherein

\mu _{1}= refractive index of medium of object

\mu _{2}= refractive index of lens

R_{1}\, and \, R_{2} are radius of curvature of two surface

 

We have

\frac{1}{f} = \frac{1}{v} - \frac{1}{u}.....1

and

\frac{1}{f} = \left ( u_{rel}-1 \right )\left ( \frac{1}{R_{1}} - \frac{1}{R_{2}} \right )

If we change urel then f will change.

If f will change for then for same u value. V value will change but screen position is not changed so image will disaapear.

 


Option 1)

Erect real image

Option 2)

Image disappears

Option 3)

Magnified image

Option 4)

 No change

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