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The Pressure extend below a column of water open to the atmosphere at depth 10m

  • Option 1)

    2.013\times 10^{5} Pa

     

     

  • Option 2)

    4.013\times 10^{5} Pa

  • Option 3)

    1.013\times 10^{5} Pa

  • Option 4)

    None

 

Answers (1)

best_answer

As we learned

 

Height of column at solution side (excess height developed) -

\pi = d\: g\: h
 

- wherein

h= excess\: height

g= accleration \: due \: to\: gravity

d= density \: of \: solution

 

 a density of water is  1\times 10^{3} Kg /m^{3}

 

g = 9.8m / sec^{2}\approx 10

P=P_{0}+hdg

        =1.013\times 10^{5}+10\times 1\times 10^{3}\times 10

        =1.013\times 10^{5}+ 1\times 10^{5}
        =2.013 \times 10^{5}pa


Option 1)

2.013\times 10^{5} Pa

 

 

Option 2)

4.013\times 10^{5} Pa

Option 3)

1.013\times 10^{5} Pa

Option 4)

None

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Plabita

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