Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Solve it, Two closed bulbs of equal volume (V) containing an ideal gas initially at pressure pi and temperature T1 are connected through a narrow tube of negligible volume as shown in the figure below. The temperature of one of the bulbs is then rais

Two closed bulbs of equal volume (V) containing an ideal gas initially at pressure pi and temperature T1 are connected through a narrow tube of negligible volume as shown in the figure below.  The temperature of one of the bulbs is then raised to T2.  The final pressure pf is :

  • Option 1)

    p_{i}\left ( \frac{T_{1}T_{2}}{T_{1}+T_{2}} \right )

  • Option 2)

    2p_{i}\left ( \frac{T_{1}}{T_{1}+T_{2}} \right )

  • Option 3)

    2p_{i}\left ( \frac{T_{2}}{T_{1}+T_{2}} \right )

  • Option 4)

    2p_{i}\left ( \frac{T_{1}T_{2}}{T_{1}+T_{2}} \right )

 

Answers (1)

best_answer

As we have learnt,

 

Boyle’s Law -

At constant Temp and moles, pressure is inversely proportional to volume of gas.

- wherein

P_{1}V_{1}= P_{2}V_{2}     

 

 

Charles’s Law -

At constant pressure and moles, volume is directly proportional to temperature of gas.

- wherein

\frac{V_{1}}{T_{1}}= \frac{V_{2}}{T_{2}}          

 

 

Gay Lussac’s Law -

Pressure -Temperature Relationship

- wherein

\frac{P_{1}}{T_{1}}= \frac{P_{2}}{T_{2}}

 

 

Avogadro’s Law -

Volume - mole relationship

- wherein

\frac{V_{1}}{n_{1}}= \frac{V_{2}}{n_{2}}

 

 Intitially,

n_1 = \frac{P_i V}{RT_1}, n_2 = \frac{P_i V}{RT_1}

Later on:

n'_1 = \frac{P_f V}{RT_1}, n'_2 = \frac{P_f V}{RT_2}

\\*\Rightarrow n_1 + n_2 = n'_2+ n'_2 \\*\Rightarrow \frac{P_i V}{RT_1} +\frac{P_i V}{RT_1} = \frac{P_f V}{RT_1} + \frac{P_f V}{RT_2} \\*\Rightarrow \frac{2P_iV}{RT_1} = \frac{P_f V}{R}\left(\frac{T_1 + T_2}{T_1T_2} \right ) \\*\Rightarrow P_f = \frac{2P_i T_2}{T_1 + T_2}

 

 

 

 


Option 1)

p_{i}\left ( \frac{T_{1}T_{2}}{T_{1}+T_{2}} \right )

Option 2)

2p_{i}\left ( \frac{T_{1}}{T_{1}+T_{2}} \right )

Option 3)

2p_{i}\left ( \frac{T_{2}}{T_{1}+T_{2}} \right )

Option 4)

2p_{i}\left ( \frac{T_{1}T_{2}}{T_{1}+T_{2}} \right )

Posted by

SudhirSol

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main Result 2024 Live: JEE April results at jeemain.nta.ac.in likely today; cutoff, rank predictor, update
anam-khan

JEE Main 2024 session 2 final answer key out at jeemain.nta.ac.in; steps to check probable scores
anam-khan

JEE Main Result 2024 Live: Download session 2 final answer key at jeemain.nta.ac.in; rank predictor, cutoff

Latest Question